sql age function

If you are after proper T-SQL Age calculation or Function then the below post might help you.

Below are questions that I try to answer in this post:

  • How to get age from birth date using getdate() (current date) in Tsql
  • How to calculate age from data of birth (DOB) and specified date
  • How to create T-SQL aging UDF function to calculate age from DOB and today's date or specified date
  • Calculate person's age (Accurate age calculation)

    T-SQL Age - years difference

    T-SQL Date of birth to Age



    T-SQL Age Calculation

    T-SQL Age Function (UDF)



    T-SQL Age Function

    T-SQL Age Calculation

      There are many example on the web of inaccurate calculation of age or date of birth. Some of them calculate it without taking into consideration month and day of month. Here is a link to one of these pages T-SQL Age (inaccurate) which tries to calculate age by dividing it by 365.25.

      Sometimes you might be after just a way to calculate difference in years and below is an example that you can use:

      SELECT DATEDIFF(Year,'1983-08-19',GETDATE()) AS AGE -- THIS IS DIFFERENCE IN YEARS

      But more ofter you want to calculate precise age and not accurate in 99% of cases but accurate in 100% of cases and below is how you can do that.

      If you would like to calcualte person's age using t-sql by converting person's date of birth to age then the below t-sql statement might help you.

      -- first we declare date of birth and the date we want to compare it to (usually today's date).
      DECLARE @DOB AS DATETIME
      SET @DOB = '1983-08-19'
      DECLARE @CompareDate AS DATETIME
      SET @CompareDate = GETDATE()

      -- below is t-sql statement that performs the actual conversion from date of birt to age.
      SELECT CASE WHEN (MONTH(@CompareDate)*100)+DAY(@CompareDate) >= (MONTH(@DOB)*100)+DAY(@DOB)
      THEN DATEDIFF(Year,@DOB,@CompareDate) ELSE DATEDIFF(Year,@DOB,@CompareDate)-1 END AS Age
      -- below example is the same above but based on field from database and getdate()
      SELECT CASE WHEN (MONTH(GETDATE())*100)+DAY(GETDATE()) >= (MONTH(DOB_Field)*100)+DAY(DOB_Field)
      THEN DATEDIFF(Year,DOB_Field,GETDATE()) ELSE DATEDIFF(Year,DOB_Field,GETDATE())-1 END AS Age

      -- and another t-sql statement but based on both dob field from database and comparedate from database as well.
      SELECT CASE WHEN (MONTH(CompareDate_Field)*100)+DAY(CompareDate_Field) >= (MONTH(DOB_Field)*100)+DAY(DOB_Field)
      THEN DATEDIFF(Year,DOB_Field,CompareDate_Field) ELSE DATEDIFF(Year,DOB_Field,CompareDate_Field)-1 END AS Age

      The link provides an alternative calculation T-SQL Age (also accurate)
      Below is T-SQL Age Function (UDF) which you can use and modify. Please be aware that it was created using SQL Server 2008 R2 function so it might not work on 2008 or 2005 without version adjustments.

      CREATE FUNCTION [dbo].[udfCalculateAge]
      (
      @DOB AS DATE,
      @EndDate as DATE = '2999-01-01' -- Defaul is today's date (see below) but any date can be used here
      )
      RETURNS TINYINT
      AS
      BEGIN
      DECLARE @Result as TINYINT

      -- IF DEFAULT VALUE (marked as 2999-01-01 as it doesn't accept functions) IS USED THEN USE TODAY'S DATE
      IF @EndDate = '2999-01-01'
      SET @EndDate = GETDATE()
      IF @DOB >= @EndDate -- trap errors
      SET @Result = 0
      ELSE
      BEGIN
      -- check if the person had its birthday in the specified year and calculate age
      IF (MONTH(@EndDate)*100)+DAY(@EndDate) >= (MONTH(@DOB)*100)+DAY(@DOB)
      SET @Result = DATEDIFF(Year,@DOB,@EndDate)
      ELSE
      SET @Result = DATEDIFF(Year,@DOB,@EndDate)-1
      END

      RETURN @Result

      END

      And below you can see the results

      Related Internal Links:
      T-SQL Current Date Related External Links:
      T-SQL DateDiff function
      T-SQL Day function
      T-SQL Month function
      Age (Wikipedia)
      Ageing (Wikipedia)


      Hope that helps!
      Emil

SHARE:


Name: product photographer miami
Comment:

i want to convert the date into the same format of getdate() to have comparision with the date passed from front.? how can i do that..?

<a href="http://www.gmgadvertising.com/corporate-branding/photography.php">product photographer miami</a>
 


Date Posted: 17/03/2012 2:45:41 PM

Name: pradeep
Comment:

I just tried with the below query to find the age from date of birth.

select empid,empname,date_of_birth,convert(int,GETDATE()-date_of_birth)/365 as "age" from dbo.employee

 

Thanks,

Pradeep


Date Posted: 16/07/2012 2:33:28 PM

Name: R. Schreurs
Comment:

Thanks for the post.

I was almost going to use:

if(datepart(y, @enddate) >= datepart(y, @dob))

but this fails in leap years when the person's date of birth is after 29th of february. Such a date is not the same day number as the same date in non-leap years.

You solution works correct.
 


Date Posted: 05/02/2013 11:37:07 AM

Name: hrothenb
Comment:

 

DECLARE @DOB DATETIME,

@later DATETIME

SELECT @DOB = '02/07/1980',

@later = '02/06/1981'

SELECT DATEDIFF(yy, @DOB, @later) -

CASE

WHEN @DOB <= DATEADD(yy, DATEDIFF(yy, @later, @DOB), @later) THEN 0

ELSE 1

END AS Age

 

SELECT CASE WHEN datepart(dayofyear, @later ) >= datepart(dayofyear, @DOB)

THEN DATEDIFF(yy,@DOB,@later)

ELSE DATEDIFF(yy,@DOB,@later) -1

END AGE

 

 

SELECT CASE

WHEN DATEPART(dayofyear, GETDATE()) >= DATEPART(dayofyear, @DOB) THEN

DATEDIFF(yy, @DOB, GETDATE())

ELSE DATEDIFF(yy, @DOB, GETDATE()) -1

END AGE

 

 


Date Posted: 20/03/2013 8:03:05 PM




Disclaimer: While every caution has been taken to provide our readers with most accurate information and honest analysis, please use your discretion before taking any decisions based on the information in this blog. Author will not compensate you in any way whatsoever if you ever happen to suffer a loss/inconvenience/damage because of/while making use of information in this blog.